ãããŒãçãã¢ã¹ãå
š4çš®å±éðªð«§
(ã€ã€ãªã³ã°ããŒãã«å€æŽå¯èœã§ãã)
ããŠãä»åã®ã¢ã³ã«ãŒã¯ðŠ.*Ëããã§ãâºïž
è¯ãã§ãããâŠè¶ã
âŠïœ¶ïŸïœ²ïœ¯âŠâŠ
è¶ãã¢ããŒããªã ãã§ããã«ãšããããŠããŸãã®ãèŸããã人éã§ãð¥²
å°ã
ãçäœããŒãã«è©°ã蟌ã¿ãããŸããŠâŠéåäœææçã®æ¹ã«ã¯åããªããããããŸããð§
ïŸïŸïŸïŸïŸèªèº«ãè¥å¹²ãããããã«ãªããŸããããæ¬äœãã¯ãªã¢ã«ããããšã«ãã£ãŠïœ·ïŸïœïœ·ïŸïœïœ¯ãšæã¯å€å°ç·©åãããŠããããšð€
ã«ã©ãã«ãªãããŒãçãã®ã¥ããšéããŠããããðŠãéãã§è¡ããšèšããã¡ã³ã¿ãžãŒèšå®ã§äœæããŸããã
å®ã¯é±ç²ã®ãã®èŒãã¯ãããŒãçã®è¹è²æåãåçž®ãããçµæ¶ãªã®ã§ãããªããŠãâºïžâšïžð
ãããŒãçãã¢ã¹ãå
š4çš®å±éðªð«§
(ã€ã€ãªã³ã°ããŒãã«å€æŽå¯èœã§ãã)
ããŠãä»åã®ã¢ã³ã«ãŒã¯ðŠ.*Ëããã§ãâºïž
è¯ãã§ãããâŠè¶ã
âŠïœ¶ïŸïœ²ïœ¯âŠâŠ
è¶ãã¢ããŒããªã ãã§ããã«ãšããããŠããŸãã®ãèŸããã人éã§ãð¥²
å°ã
ãçäœããŒãã«è©°ã蟌ã¿ãããŸããŠâŠéåäœææçã®æ¹ã«ã¯åããªããããããŸããð§
ïŸïŸïŸïŸïŸèªèº«ãè¥å¹²ãããããã«ãªããŸããããæ¬äœãã¯ãªã¢ã«ããããšã«ãã£ãŠïœ·ïŸïœïœ·ïŸïœïœ¯ãšæã¯å€å°ç·©åãããŠããããšð€
ã«ã©ãã«ãªãããŒãçãã®ã¥ããšéããŠããããðŠãéãã§è¡ããšèšããã¡ã³ã¿ãžãŒèšå®ã§äœæããŸããã
å®ã¯é±ç²ã®ãã®èŒãã¯ãããŒãçã®è¹è²æåãåçž®ãããçµæ¶ãªã®ã§ãããªããŠãâºïžâšïžð
ãµã€ãº
3.5cm
çºéãŸã§ã®ç®å®
3æ¥
é éæ¹æ³ã»éæ
å®åœ¢ïŒå€ïŒéµäŸ¿
120åïŒè¿œå éæïŒ20åïŒ
å šåœäžåŸ
å šåœäžåŸ
è³Œå ¥ã®éã®æ³šæç¹
éå±éšåã¯ã¢ã¬ã«ã®ãŒå¯ŸçããããŠããªãç©ã䜿çšããŠããã®ã§ãéå±ã¢ã¬ã«ã®ãŒã®æ¹ã¯åŸ¡é æ
®äžããðŠ
(ããã±ã«ããªãŒçã®è¯ãããªãã®ãèŠã€ãããŸã§ãã°ããããããšæããŸãããéã¢ã¬ã ãã©ïŸïŸïŸïŸïŸã®ã¢ã¯ã»ã欲ãããïŒïŒããšèšãæé£ããæ¹ã«ã¯ä»æ«ããåŸ
ããèŽããŸãðð»ââïž)
ã¬ãžã³äœåã¯çŽ«å€ç·ã«åŒ±ãã®ã§ãä¿ç®¡ããéã¯çŽå°æ¥å
ã®åœãããªã æãå Žæã«é ããŠé ãããšç¶ºéºãé·æã¡ããŸãâš